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PHP AjaxForm提交图片上传并显示图片源码

更新时间:2020-03-15 11:44:18 作者:startmvc
本文实例为大家分享了PHPAjaxForm提交图片上传并显示图片的具体代码,供大家参考,具体内

本文实例为大家分享了PHP AjaxForm提交图片上传并显示图片的具体代码,供大家参考,具体内容如下

PHP dofile.php 文件上传源码


<?php
$file_upload = "upload/";
$file_allow_ext='gif|jpg|jpeg|png|gif|zip|rar|ppt|xls|pdf|pptx|xlsx|docx';
$file_allow_size = 5*1024*1024;
if($_POST['submit']=="上传"){
 if(is_uploaded_file($_FILES['file']['tmp_name'])){
 $file_name = $_FILES['file']['name'];
 $file_error = $_FILES['file']['error'];
 $file_type = $_FILES['file']['type'];
 $file_tmp_name = $_FILES['file']['tmp_name']; 
 $file_size = $_FILES['file']['size'];
 $file_ext = substr($file_name, strrpos($file_name, '.')+1);
 switch($file_error){
 case 0:
 $data['status'] = 0;
 $data['msg'] = "文件上传成功!"; 
 break;

 case 1:
 $data['status'] = 1;
 $data['msg'] = "文件上传失败,文件大小".$file_size."超过限制,允许上传大小".sizeFormat($file_allow_size)."!"; 
 break;

 case 3:
 $data['status'] = 1;
 $data['msg'] = "上传失败,文件只有部份上传!"; 
 break;

 case 4:
 $data['status'] = 1;
 $data['msg'] = "上传失败,文件没有被上传!"; 
 break;

 case 5:
 $data['status'] = 1;
 $data['msg'] = "文件上传失败,文件大小为0!"; 
 break; 
 }
 if(stripos($file_allow_ext,$file_ext)===false){
 $data['status'] = 1;
 $data['msg'] = "该文件扩展名不允许上传"; 
 }
 if($file_size>$file_allow_size){ 
 $data['status'] = 1;
 $data['msg'] = "文件大小超过限制,只能上传".sizeFormat($file_allow_size)."的文件!"; 
 } 
 if($data['status']==1){
 $data['status'] = 1;
 $data['msg'] = $data['msg'];
 exit(json_encode($data)); 
 }
 if($data['status']==0){
 if(file_exists($file_upload)){ 
 $file_new_name = date("YmdHis").'_'.rand(10000,99999).'.'.$file_ext;
 $file_save_path = $file_upload.$file_new_name; 
 $data['status'] = 0; 
 $data['url'] = $file_save_path;
 move_uploaded_file($file_tmp_name,$file_save_path);
 exit(json_encode($data)); 
 }else{
 exit(json_encode($data));
 } 

 } 
 }
}

function sizeFormat($size)
{
 $sizeStr='';
 if($size<1024)
 {
 return $size."bytes";
 }
 else if($size<(1024*1024))
 {
 $size=round($size/1024,1);
 return $size."KB";
 }
 else if($size<(1024*1024*1024))
 {
 $size=round($size/(1024*1024),1);
 return $size."MB";
 }
 else
 {
 $size=round($size/(1024*1024*1024),1);
 return $size."GB";
 } 
}



?>


HTML如下


<script type="text/javascript" src="http://lib.sinaapp.com/js/jquery/1.9.1/jquery-1.9.1.min.js"></script>
<script type="text/javascript" src="http://files.cnblogs.com/files/china-li/jquery.form.js"></script>

<form action="dofile.php" method="post" enctype="multipart/form-data" id="upfileimage">
<input type="hidden" name="image[]" />
<label for="file">文件:</label><input type="file" name="file" id="file" />
<input type="submit" name="submit" value="上传" />
</form>

<script type="text/javascript">
$("#upfileimage").submit(function(){
 if($("input[type=file]").val()==""){
 alert("请选择要上传的文件");
 return false;
 }
})
$(function(){
 var options = { 
 type:"POST",
 dataType:"json",
 resetForm:true,
 success:function(o){
 if(o.status==1){
 alert(o.msg);
 }else{
 $("body").append("  <img src='"+o.url+"' alt='' width='100' /><input type='hidden' name='image[]' value='"+o.url+"' />");
 }
 },
 error:function(o){
 alert(o.message);
 } 
 }
 $("#upfileimage").ajaxForm(options).submit(function(){return false;});

})
</script>

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

PHP AjaxForm 图片上传