php实现用于验证所有类型的信用卡类

本文实例讲述了php实现用于验证所有类型的信用卡类。分享给大家供大家参考。具体如下：

本文实例讲述了php实现用于验证所有类型的信用卡类。分享给大家供大家参考。具体如下：

这个php类比较完整，可以用于验证各种不同的信用卡，针对信用卡的卡号的通用规则进行了验证，同时对不同类型的信用卡进行了针对性的识别。 代码接受一个信用卡号码和有效日期，如果两者都有效，则返回TRUE,否则返回FALSE。

本插件接受以下参数： $number 表示信用卡号码的一个字符串 $expiry 信用卡有效日期，采用07/12或0712这样的格式

<?php
// Plug-in 32: Validate Credit Card
// This is an executable example with additional code supplied
// To obtain just the plug-ins please click on the Download link
$card = "4567 1234 5678 9101";
$exp = "06/11";
echo "Validating: $card : $exp<br>";
$result = PIPHP_ValidateCC($card, $exp);
if ($result != FALSE) echo "Card Validated";
else echo "Card did not validate";
function PIPHP_ValidateCC($number, $expiry)
{
 // Plug-in 32: Validate Credit Card
 //
 // This plug-in accepts a credit card number and
 // an expiry date and returns TRUE or FALSE,
 // depending on whether the details pass date
 // and checksum validation. The arguments required
 // are:
 //
 // $number: Credit Card Number
 // $expiry: Expiry date in the form:
 // 07/12 or 0712 (for July, 2012)
 $number = preg_replace('/[^\d]/', '', $number);
 $expiry = preg_replace('/[^\d]/', '', $expiry);
 $left = substr($number, 0, 4);
 $cclen = strlen($number);
 $chksum = 0;
 // Diners Club
 if (($left >= 3000) && ($left <= 3059) ||
 ($left >= 3600) && ($left <= 3699) ||
 ($left >= 3800) && ($left <= 3889))
 if ($cclen != 14) return FALSE;
 // JCB
 if (($left >= 3088) && ($left <= 3094) ||
 ($left >= 3096) && ($left <= 3102) ||
 ($left >= 3112) && ($left <= 3120) ||
 ($left >= 3158) && ($left <= 3159) ||
 ($left >= 3337) && ($left <= 3349) ||
 ($left >= 3528) && ($left <= 3589))
 if ($cclen != 16) return FALSE;
 // American Express
 elseif (($left >= 3400) && ($left <= 3499) ||
 ($left >= 3700) && ($left <= 3799))
 if ($cclen != 15) return FALSE;
 // Carte Blanche
 elseif (($left >= 3890) && ($left <= 3899))
 if ($cclen != 14) return FALSE;
 // Visa
 elseif (($left >= 4000) && ($left <= 4999))
 if ($cclen != 13 && $cclen != 16) return FALSE;
 // MasterCard
 elseif (($left >= 5100) && ($left <= 5599))
 if ($cclen != 16) return FALSE;
 // Australian BankCard
 elseif ($left == 5610)
 if ($cclen != 16) return FALSE;
 // Discover
 elseif ($left == 6011)
 if ($cclen != 16) return FALSE;
 // Unknown
 else return FALSE;
 for ($j = 1 - ($cclen % 2); $j < $cclen; $j += 2)
 $chksum += substr($number, $j, 1);
 for ($j = $cclen % 2; $j < $cclen; $j += 2)
 {
 $d = substr($number, $j, 1) * 2;
 $chksum += $d < 10 ? $d : $d - 9;
 }
 if ($chksum % 10 != 0) return FALSE;
 if (mktime(0, 0, 0, substr($expiry, 0, 2), date("t"),
 substr($expiry, 2, 2)) < time()) return FALSE;
 return TRUE;
}
?>

希望本文所述对大家的php程序设计有所帮助。