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python与sqlite3实现解密chrome cookie实例代码

更新时间:2020-05-19 00:06:01 作者:startmvc
本文研究的主要问题:有一个解密chromecookie的事情,google出了代码,却不能正常执行,原因

本文研究的主要问题:有一个解密chrome cookie的事情,google出了代码,却不能正常执行,原因在于sqlite3的版本太低,虽然我切换到了python3.5的环境,但sqlite3的版本也只有3.6。

google了许久,终于找到方法:

1、 进入页面 http://www6.atomicorp.com/channels/atomic/centos/6/x86_64/RPMS/

2、 下载 atomic-sqlite-sqlite-3.8.5-2.el6.art.x86_64.rpm

3、 rpm -Uvh atomic-sqlite-sqlite-3.8.5-2.el6.art.x86_64.rpm

4、 执行命令 sqlite3 -version 一切都ok啦

顺便附上解析cookie的代码


#coding=utf-8 
import os 
import sqlite3 
 
#import keyring 
from Crypto.Cipher import AES 
from Crypto.Protocol.KDF import PBKDF2 
 
#for mac 
#my_pass = keyring.get_password('Chrome Safe Storage', 'Chrome') 
#my_pass = my_pass.encode('utf8') 
#iterations = 1003 
#cookie_file = os.path.expanduser('~/Library/Application Support/Google/Chrome/Default/Cookies') 
 
#for linux 
my_pass = 'peanuts'.encode('utf8') 
iterations = 1 
cookie_file = 'Cookies' 
 
salt = b'saltysalt' 
length = 16 
iv = b' ' * length 
 
 
 
def expand_str(token): 
 token_len = len(token) 
 expand_len = (token_len // length + 1) * length - token_len 
 return token.encode('ascii') + b'\x0c' * expand_len 
 
 
def aes_encrypt(token): 
 key = PBKDF2(my_pass, salt, length, iterations) 
 cipher = AES.new(key, AES.MODE_CBC, IV=iv) 
 enc_token = cipher.encrypt(token) 
 return b'v10' + enc_token 
 
 
def aes_decrypt(token): 
 key = PBKDF2(my_pass, salt, length, iterations) 
 cipher = AES.new(key, AES.MODE_CBC, IV=iv) 
 dec_token = cipher.decrypt(token) 
 return dec_token 
 
 
def query_cookies(): 
 with sqlite3.connect(cookie_file) as conn: 
 sql = "select host_key, name, encrypted_value from cookies where name = 'jzysYonghu'" 
 #sql = "select * from cookies" 
 result = conn.execute(sql).fetchall() 
 return result 
 
 
def write_cookies(enc_token): 
 with sqlite3.connect(cookie_file) as conn: 
 b = sqlite3.Binary(enc_token) 
 sql = """update cookies set encrypted_value = ? where name = 'remember_token'""" 
 conn.execute(sql, (b, )) 
 
def change_user(token): 
 write_cookies(ase_encrypt(expand_str(token))) 
 
if __name__ == '__main__': 
 data = query_cookies()[0][2] 
 print(data) 
 print(len(data)) 
 print(aes_decrypt(data[3:])) 

加密后在字符串前面添加了一个v10,因此解密前要先去掉

总结

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