Python制作Windows系统服务

最近有个Python程序需要安装并作为Windows系统服务来运行，过程中碰到一些坑，整理了一下。

Python服务类

首先Python程序需要调用一些Windows系统API才能作为系统服务，具体内容如下：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sys
import time

import win32api
import win32event
import win32service
import win32serviceutil
import servicemanager


class MyService(win32serviceutil.ServiceFramework):

 _svc_name_ = "MyService"
 _svc_display_name_ = "My Service"
 _svc_description_ = "My Service"

 def __init__(self, args):
 self.log('init')
 win32serviceutil.ServiceFramework.__init__(self, args)
 self.stop_event = win32event.CreateEvent(None, 0, 0, None)

 def SvcDoRun(self):
 self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
 try:
 self.ReportServiceStatus(win32service.SERVICE_RUNNING)
 self.log('start')
 self.start()
 self.log('wait')
 win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
 self.log('done')
 except BaseException as e:
 self.log('Exception : %s' % e)
 self.SvcStop()

 def SvcStop(self):
 self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
 self.log('stopping')
 self.stop()
 self.log('stopped')
 win32event.SetEvent(self.stop_event)
 self.ReportServiceStatus(win32service.SERVICE_STOPPED)

 def start(self):
 time.sleep(10000)

 def stop(self):
 pass

 def log(self, msg):
 servicemanager.LogInfoMsg(str(msg))

 def sleep(self, minute):
 win32api.Sleep((minute*1000), True)

if __name__ == "__main__":
 if len(sys.argv) == 1:
 servicemanager.Initialize()
 servicemanager.PrepareToHostSingle(MyService)
 servicemanager.StartServiceCtrlDispatcher()
 else:
 win32serviceutil.HandleCommandLine(MyService)

pyinstaller打包

pyinstaller -F MyService.py

测试

# 安装服务
dist\MyService.exe install

# 启动服务
sc start MyService

# 停止服务
sc stop MyService

# 删除服务
sc delete MyService

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。