Python字典实现简单的三级菜单(实例讲解)

如下所示：data={"北京":{"昌平":{"沙河":["oldboy","test"],"天通苑":["链接地产","我爱我家"]},"朝阳

如下所示：

data = {
 "北京":{
 "昌平":{"沙河":["oldboy","test"],"天通苑":["链接地产","我爱我家"]},
 "朝阳":{"望京":["奔驰","陌陌"],"国贸":["CICC","HP"],"东直门":["advent","飞信"]},
 "海淀":{}
 },
 "山东":{
 "德州":{},
 "青岛":{},
 "济南":{}
 },
 "广东":{
 "东莞":{},
 "常熟":{},
 "佛山":{}
 }
}
exit_flag = False
while not exit_flag:
 for i in data:
 print(i)
 choice_s = input("请输入以上任一省或直辖市名称>>>:")
 if choice_s in data:
 while not exit_flag:
 for i in data[choice_s]:
 print("\t",i)
 choice_q = input("请输入以上任一市区名称>>>:")
 if choice_q in data[choice_s]:
 while not exit_flag:
 for i in data[choice_s][choice_q]:
 print("\t\t",i)
 choice_j = input("请输入以上任一街道名称>>>:")
 if choice_j in data[choice_s][choice_q]:
 for i in data[choice_s][choice_q][choice_j]:
 print("\t\t",i)
 last = input("最后一层，按b返回>>>:")
 if last == "b":
 pass
 elif last == "q":
 exit_flag = True
 if choice_j == "b":
 break
 elif choice_j == "q":
 exit_flag = True
 if choice_q == "b":
 break
 elif choice_q == "q":
 exit_flag = True

要点：

1、字典的层级关系

2、break是终止本次循环，pass是什么也不做，一个占位符而已

3、巧妙使用exit_flag = False

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