Python3调用微信企业号API发送文本消息代码示例

本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：#!

本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：

#!/usr/bin/env python
# -*- coding:utf-8 -*-
import urllib.request
import json
import sys
import logging
touser = '@all'
agentid = 0
corpid = 'wx5aef2da956514535'
corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'
url = 'https://qyapi.weixin.qq.com'
subject = sys.argv[2]
message = sys.argv[3]
logging.basicConfig(level=logging.DEBUG, filename='E:\Python_project\Scripts\my.log',
 format='%(asctime)s - %(levelname)s: %(message)s')
class Weixin:
 def __init__(self, url, corpid, corpsecret):
 token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url, corpid, corpsecret)
 self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']
 def send_message(self, url, data):
 send_url = '%s/cgi-bin/message/send?access_token=%s' % (url, self.token)
 self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url, data=data)).read()
 x = json.loads(self.respone.decode())['errcode']
 if x == 0:
 logging.debug('Successfully %s %s' % (subject, message))
 return 'Succesfully'
 else:
 logging.debug('Failed %s %s' % (subject, message))
 return 'Failed'
 def messages(self, subject, message):
 values = {
 "touser": touser,
 "msgtype": 'text',
 "agentid": agentid,
 "text": {'content': subject + message},
 "safe": 0
 }
 return self.send_message(url, bytes(json.dumps(values), 'utf-8'))
if __name__ == '__main__':
 obj = Weixin(url, corpid, corpsecret)
 ret = obj.messages(subject, message)

总结

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