d3.js实现立体柱图的方法详解

更新时间：2020-05-09 15:12:01 作者：startmvc

前言众所周知随着大数据时代的来临,数据可视化的重要性也越来越凸显,那么今天就基于d3.j

前言

众所周知随着大数据时代的来临,数据可视化的重要性也越来越凸显,那么今天就基于d3.js今天给大家带来可视化基础图表柱图进阶:立体柱图，之前介绍过了d3.js实现柱状图的文章，感兴趣的朋友们可以看一看。

关于d3.js

d3.js是一个操作svg的图表库,d3封装了图表的各种算法.对d3不熟悉的朋友可以到d3.js官网学习d3.js.

另外感谢司机大傻(声音像张学友一样性感的一流装逼手)和司机呆(呆萌女神)等人对d3.js进行翻译!

HTML+CSS


<!DOCTYPE html>
<html lang="en">
<head>
 <meta charset="UTF-8">
 <title>Title</title>
 <style>
 * {
 margin: 0;
 padding: 0;
 }

 div.tip-hill-div {
 background: rgba(0, 0, 0, 0.7);
 color: #fff;
 padding: 10px;
 border-radius: 5px;
 font-family: Microsoft Yahei;
 }

 div.tip-hill-div > h1 {
 font-size: 14px;
 }

 div.tip-hill-div > h2 {
 font-size: 12px;
 }
 </style>
</head>
<body>
<div id="chart"></div>
</body>
</html>

当前使用d3.v4+版本


<script src="d3-4.js"></script>

图表所需数据


var data = [{
 "letter": "白皮鸡蛋",
 "child": {
 "category": "0",
 "value": "459.00"
 }
 }, {
 "letter": "红皮鸡蛋",
 "child": {
 "category": "0",
 "value": "389.00"
 }
 }, {
 "letter": "鸡蛋",
 "child": {
 "category": "0",
 "value": "336.00"
 }
 }, {
 "letter": "牛肉",
 "child": {
 "category": "0",
 "value": "282.00"
 }
 }, {
 "letter": "羊肉",
 "child": {
 "category": "0",
 "value": "249.00"
 }
 }, {
 "letter": "鸭蛋",
 "child": {
 "category": "0",
 "value": "242.00"
 }
 }, {
 "letter": "红薯",
 "child": {
 "category": "0",
 "value": "222.00"
 }
 }, {
 "letter": "白菜",
 "child": {
 "category": "0",
 "value": "182.00"
 }
 }, {
 "letter": "鸡肉",
 "child": {
 "category": "0",
 "value": "102.00"
 }
 }];

图表的一些基础配置数据


var margin = {
 top: 20,
 right: 50,
 bottom: 50,
 left: 90
 };

var svgWidth = 1000;
var svgHeight = 500;


//创建各个面的颜色数组
var mainColorList = ['#f6e242', '#ebec5b', '#d2ef5f', '#b1d894','#97d5ad', '#82d1c0', '#70cfd2', '#63c8ce', '#50bab8', '#38a99d'];
var topColorList = ['#e9d748', '#d1d252', '#c0d75f', '#a2d37d','#83d09e', '#68ccb6', '#5bc8cb', '#59c0c6', '#3aadab', '#2da094'];
var rightColorList = ['#dfce51', '#d9db59', '#b9d54a', '#9ece7c','#8ac69f', '#70c3b1', '#65c5c8', '#57bac0', '#42aba9', '#2c9b8f'];

var svg = d3.select('#chart')
 .append('svg')
 .attr('width', svgWidth)
 .attr('height', svgHeight)
 .attr('id', 'svg-column');

创建X轴序数比例尺


function addXAxis() {
 var transform = d3.geoTransform({
 point: function (x, y) {
 this.stream.point(x, y)
 }
 });
 //定义几何路径
 var path = d3.geoPath()
 .projection(transform);

 xLinearScale = d3.scaleBand()
 .domain(data.map(function (d) {
 return d.letter;
 }))
 .range([0, svgWidth - margin.right - margin.left], 0.1);
 var xAxis = d3.axisBottom(xLinearScale)
 .ticks(data.length);
 //绘制X轴
 var xAxisG = svg.append("g")
 .call(xAxis)
 .attr("transform", "translate(" + (margin.left) + "," + (svgHeight - margin.bottom) + ")");

 //删除原X轴
 xAxisG.select("path").remove();
 xAxisG.selectAll('line').remove();
 //绘制新的立体X轴
 xAxisG.append("path")
 .datum({
 type: "Polygon",
 coordinates: [
 [
 [20, 0],
 [0, 15],
 [svgWidth - margin.right - margin.left, 15],
 [svgWidth + 20 - margin.right - margin.left, 0],
 [20, 0]
 ]
 ]
 })
 .attr("d", path)
 .attr('fill', 'rgb(187,187,187)');
 xAxisG.selectAll('text')
 .attr('font-size', '18px')
 .attr('fill', '#646464')
 .attr('transform', 'translate(0,20)');

 dataProcessing(xLinearScale)//核心算法
 }

你可能注意到了,上面代码中不仅使用了序数比例尺,还有地理路径生成器,因为需要生成立体的柱图,所以需要讲原本的X轴删除,自己重新进行绘制.下图是自己重新绘制出来的path路径:

创建Y轴线性比例尺


var yLinearScale;
 //创建y轴的比例尺渲染y轴
 function addYScale() {
 yLinearScale = d3.scaleLinear()
 .domain([0, d3.max(data, function (d, i) {
 return d.child.value * 1;
 }) * 1.2])
 .range([svgHeight - margin.top - margin.bottom, 0]);

 //定义Y轴比例尺以及刻度
 var yAxis = d3.axisLeft(yLinearScale)
 .ticks(6);

 //绘制Y轴
 var yAxisG = svg.append("g")
 .call(yAxis)
 .attr('transform', 'translate(' + (margin.left + 10) + "," + margin.top + ")");
 yAxisG.selectAll('text')
 .attr('font-size', '18px')
 .attr('fill', '#636363');
 //删除原Y轴路径和tick
 yAxisG.select("path").remove();
 yAxisG.selectAll('line').remove();
 }

创建Y轴时同样需要把原来的路径和tick删除,下图是效果:

到这,我们的基础搭建完毕,下面就是核心算法

核心算法

为了实现最终效果,我希望大家在理解的时候能把整个立体柱图分解一下.

我实现立体柱图的思路是通过2个path路径和一个rect进行拼凑.

正面是一个rect,上面和右面利用path路径生成.

利用三角函数,通过给定的angle角度计算上面的一个点就可以知道其他所有点的位置进而进行绘制.

通过上图可以看到,一个立体柱图我们只需要知道7个点的位置就能够绘制出来.

并且已知正面rect4个红色点的位置.已知柱子的宽度和高度,那么只要求出Top面左上角点的位置,就可以知道余下绿色点的位置.具体算法如下:


//核心算法思路是Big boss教的,我借花献佛
function dataProcessing(xLinearScale) {
 var angle = Math.PI / 2.3;
 for (var i = 0; i < data.length; i++) {
 var d = data[i];
 var depth = 10; 
 d.ow = xLinearScale.bandwidth() * 0.7;
 d.ox = xLinearScale(d.letter);
 d.oh = 1;
 d.p1 = {
 x: Math.cos(angle) * d.ow,
 y: -Math.sin(angle) - depth
 };
 d.p2 = {
 x: d.p1.x + d.ow,
 y: d.p1.y
 };
 d.p3 = {
 x: d.p2.x,
 y: d.p2.y + d.oh
 };
 }
 }

渲染

最终我们还要鼠标进行交互,所以先添加tip生成函数


//tip的创建方法(方法来自敬爱的鸣哥)
 var tipTimerConfig = {
 longer: 0,
 target: null,
 exist: false,
 winEvent: window.event,
 boxHeight: 398,
 boxWidth: 376,
 maxWidth: 376,
 maxHeight: 398,
 tooltip: null,

 showTime: 3500,
 hoverTime: 300,
 displayText: "",
 show: function (val, e) {
 "use strict";
 var me = this;

 if (e != null) {
 me.winEvent = e;
 }

 me.displayText = val;

 me.calculateBoxAndShow();

 me.createTimer();
 },
 calculateBoxAndShow: function () {
 "use strict";
 var me = this;
 var _x = 0;
 var _y = 0;
 var _w = document.documentElement.scrollWidth;
 var _h = document.documentElement.scrollHeight;
 var wScrollX = window.scrollX || document.body.scrollLeft;
 var wScrollY = window.scrollY || document.body.scrollTop;
 var xMouse = me.winEvent.x + wScrollX;
 if (_w - xMouse < me.boxWidth) {
 _x = xMouse - me.boxWidth - 10;
 } else {
 _x = xMouse;
 }

 var _yMouse = me.winEvent.y + wScrollY;
 if (_h - _yMouse < me.boxHeight + 18) {
 _y = _yMouse - me.boxHeight - 25;
 } else {

 _y = _yMouse + 18;
 }

 me.addTooltip(_x, _y);
 },
 addTooltip: function (page_x, page_y) {
 "use strict";
 var me = this;

 me.tooltip = document.createElement("div");
 me.tooltip.style.left = page_x + "px";
 me.tooltip.style.top = page_y + "px";
 me.tooltip.style.position = "absolute";

 me.tooltip.style.width = me.boxWidth + "px";
 me.tooltip.style.height = me.boxHeight + "px";
 me.tooltip.className = "three-tooltip";

 var divInnerHeader = me.createInner();
 divInnerHeader.innerHTML = me.displayText;
 me.tooltip.appendChild(divInnerHeader);

 document.body.appendChild(me.tooltip);
 },
 createInner: function () {
 "use strict";
 var me = this;
 var divInnerHeader = document.createElement('div');
 divInnerHeader.style.width = me.boxWidth + "px";
 divInnerHeader.style.height = me.boxHeight + "px";
 return divInnerHeader;
 },
 ClearDiv: function () {
 "use strict";
 var delDiv = document.body.getElementsByClassName("three-tooltip");
 for (var i = delDiv.length - 1; i >= 0; i--) {
 document.body.removeChild(delDiv[i]);
 }
 },
 createTimer: function (delTarget) {
 "use strict";
 var me = this;
 var delTip = me.tooltip;
 var delTarget = tipTimerConfig.target;
 var removeTimer = window.setTimeout(function () {
 try {
 if (delTip != null) {
 document.body.removeChild(delTip);
 if (tipTimerConfig.target == delTarget) {
 me.exist = false;
 }
 }
 clearTimeout(removeTimer);
 } catch (e) {
 clearTimeout(removeTimer);
 }
 }, me.showTime);
 },
 hoverTimerFn: function (showTip, showTarget) {
 "use strict";
 var me = this;

 var showTarget = tipTimerConfig.target;

 var hoverTimer = window.setInterval(function () {
 try {
 if (tipTimerConfig.target != showTarget) {
 clearInterval(hoverTimer);
 } else if (!tipTimerConfig.exist && (new Date()).getTime() - me.longer > me.hoverTime) {
 //show
 tipTimerConfig.show(showTip);
 tipTimerConfig.exist = true;
 clearInterval(hoverTimer);
 }
 } catch (e) {
 clearInterval(hoverTimer);
 }
 }, tipTimerConfig.hoverTime);
 }
 };

 var createTooltipTableData = function (info) {
 var ary = [];
 ary.push("<div class='tip-hill-div'>");
 ary.push("<h1>品种信息:" + info.letter + "</h1>");
 ary.push("<h2>成交量: " + info.child.value);
 ary.push("</div>");
 return ary.join("");
 };

核心算法写完,就到了最终的渲染了


function addColumn() {
 function clumnMouseover(d) {
 d3.select(this).selectAll(".transparentPath").attr("opacity", 0.8);
 // 添加 div
 tipTimerConfig.target = this;
 tipTimerConfig.longer = new Date().getTime();
 tipTimerConfig.exist = false;
 //获取坐标
 tipTimerConfig.winEvent = {
 x: event.clientX - 100,
 y: event.clientY
 };
 tipTimerConfig.boxHeight = 50;
 tipTimerConfig.boxWidth = 140;

 //hide
 tipTimerConfig.ClearDiv();
 //show
 tipTimerConfig.hoverTimerFn(createTooltipTableData(d));
 }

 function clumnMouseout(d) {
 d3.select(this).selectAll(".transparentPath").attr("opacity", 1);
 tipTimerConfig.target = null;
 tipTimerConfig.ClearDiv();
 }

 var g = svg.selectAll('.g')
 .data(data)
 .enter()
 .append('g')
 .on("mouseover", clumnMouseover)
 .on("mouseout", clumnMouseout)
 .attr('transform', function (d) {
 return "translate(" + (d.ox + margin.left + 20) + "," + (svgHeight - margin.bottom + 15) + ")"
 });
 g.transition()
 .duration(2500)
 .attr("transform", function (d) {
 return "translate(" + (d.ox + margin.left + 20) + ", " + (yLinearScale(d.child.value) + margin.bottom - 15) + ")"
 });

 g.append('rect')
 .attr('x', 0)
 .attr('y', 0)
 .attr("class", "transparentPath")
 .attr('width', function (d, i) {
 return d.ow;
 })
 .attr('height', function (d) {
 return d.oh;
 })
 .style('fill', function (d, i) {
 return mainColorList[i]
 })
 .transition()
 .duration(2500)
 .attr("height", function (d, i) {
 return svgHeight - margin.bottom - margin.top - yLinearScale(d.child.value);
 });

 g.append('path')
 .attr("class", "transparentPath")
 .attr('d', function (d) {
 return "M0,0 L" + d.p1.x + "," + d.p1.y + " L" + d.p2.x + "," + d.p2.y + " L" + d.ow + ",0 L0,0";
 })
 .style('fill', function (d, i) {
 return topColorList[i]
 });

 g.append('path')
 .attr("class", "transparentPath")
 .attr('d', function (d) {
 return "M" + d.ow + ",0 L" + d.p2.x + "," + d.p2.y + " L" + d.p3.x + "," + d.p3.y + " L" + d.ow + "," + d.oh + " L" + d.ow + ",0"
 })
 .style('fill', function (d, i) {
 return rightColorList[i]
 })
 .transition()
 .duration(2500)
 .attr("d", function (d, i) {
 return "M" + d.ow + ",0 L" + d.p2.x + "," + d.p2.y + " L" + d.p3.x + "," + (d.p3.y + svgHeight - margin.top - margin.bottom - yLinearScale(d.child.value)) + " L" + d.ow + "," + (svgHeight - margin.top - margin.bottom - yLinearScale(d.child.value)) + " L" + d.ow + ",0"
 });
 }

由于需要考虑动画,所以对渲染时的柱子位置进行了处理.对这方面不理解的话可以留言讨论.

总结

以上就是这篇文章的全部内容了，希望本文的内容对大家学习或者工作能带来一定的帮助，如果有疑问大家可以留言交流，谢谢大家对脚本之家的支持。

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文章分类

d3.js实现立体柱图的方法详解

JavaScript

d3.js实现立体柱图的方法详解