python

超轻量级php框架startmvc

python实现简易通讯录修改版

更新时间:2020-05-24 12:06:01 作者:startmvc
描述:上一篇博客我写了一个简单的通讯录,但是还是觉得不够完美:需要输入ID,虽然ID

描述:

上一篇博客我写了一个简单的通讯录,但是还是觉得不够完美:

需要输入ID,虽然ID是主键,但是没有实现自增功能;

忘记加电话号码了;

如果插入用户名相同,则后续的查、改、删功能受到影响;

所以,我这个修改版主要修正了以上三点缺陷。具体如下

将用户ID设置为自增字段,即就是不用输入ID,程序会自动帮你将插入的用户进行排序并附上ID,默认从1开始;SQLite实现主键自增功能,请查看SQLiteAUTOINCREMENT/自动递增这篇博客。 创建表时增加了电话号码字段; 插入的用户名不能重复; 好了,废话不多说,附上新代码,哈哈~~~


#-*- coding:utf-8 -*-

import sqlite3
#打开本地数据库用于存储用户信息
conn = sqlite3.connect('mysql_person.db')

#在该数据库下创建表,创建表的这段代码在第一次执行后需要注释掉,否则再次执行程序会一直提示:该表已存在
conn.execute ('''CREATE TABLE MT_table1(
 ID INTEGER PRIMARY KEY AUTOINCREMENT,
 NAME TEXT NOT NULL,
 AGE INT NOT NULL,
 ADDRESS CHAR(50),
 SALARY REAL,
 PhoneNumber INT NOT NULL);''')
print "Table created successfully";

#增加用户信息
def insert():
 USER_NAME = raw_input('请输入用户昵称:')
 cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%USER_NAME)
 for row in cursor:
 if USER_NAME == row[0]:
 print "sorry,改用户名已存在,请重新输入用户名"
 break
 else:
 AGE = input('请输入年龄:')
 ADDRESS = raw_input('请输入用户地址:')
 SALARY = input('请输入用户薪水:')
 PhoneNumber = input("请输入联系方式:")
 #为避免代码太长,以下我用字符串的连接特性将代码缩短
 sql1 = 'INSERT INTO MT_table1(NAME,AGE,ADDRESS,SALARY,PhoneNumber)'
 sql1 += 'VALUES("%s","%d","%s","%d","%d");'%(USER_NAME,AGE,ADDRESS,SALARY,PhoneNumber)
 conn.execute(sql1)
 conn.commit()
 print "Records insert successfully"

#删除用户信息
def delete():
 delete_name = raw_input("请输入所要删除的联系人姓名:")
 cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%delete_name)
 for row in cursor:
 if delete_name == row[0]:
 conn.execute("DELETE from MT_table1 where name = '%s';"%delete_name)
 conn.commit()
 print "Records delete successfully"
 break
 else:
 print "sorry,不存在该用户"

#修改用户信息
def modify():
 update_name = raw_input("请输入要修改用户的姓名:")
 sql6 = "SELECT name from MT_table1 where name = '%s';"%update_name
 cursor = conn.execute(sql6)
 for row in cursor:
 if update_name == row[0]:
 New_addr = raw_input("请输入要修改用户的新地址:")
 New_age = input("请输入要修改用户的新年龄:")
 New_salary = input("请输入要修改用户的新薪水:")
 New_num = input("输入要修改用户的新号码:")
 sql3 = "UPDATE MT_table1 set address = '%s',age = '%d',salary = '%d',PhoneNumber = '%d' where \
 name = '%s';"%(New_addr,New_age,New_salary,New_num,update_name)
 conn.execute(sql3)
 conn.commit()
 print "修改成功"
 sql5 = "SELECT id, name, age,address, salary ,PhoneNumber from MT_table1 where name = '%s';"%update_name
 cursor = conn.execute(sql5)
 for row in cursor:
 print "ID = ", row[0]
 print "NAME = ", row[1]
 print "AGE = ",row[2]
 print "ADDRESS = ", row[3]
 print "SALARY = ", row[4]
 print "PhoneNumber = ",row[5], "\n"
 break
 else:
 print "sorry,不存在该用户信息"


#查询用户信息
def search():
 conn = sqlite3.connect('mysql_person.db')
 search_name = raw_input('请输入要查询的用户姓名')
 sql2 = "SELECT id,name,age, address, salary ,PhoneNumber from MT_table1 where name= '%s';" % (search_name)
 cursor = conn.execute(sql2)
 for row in cursor:
 print "ID = ", row[0]
 print "NAME = ", row[1]
 print "AGE = ",row[2]
 print "ADDRESS = ", row[3]
 print "SALARY = ", row[4]
 print "PhoneNumber = ",row[5], "\n"
 break
 else:
 print "sorry,没有该用户信息"


#显示所有用户信息
def showall():
 cursor = conn.execute("SELECT id, name,age, address, salary ,PhoneNumber from MT_table1")
 for row in cursor:
 print "ID = ", row[0]
 print "NAME = ", row[1]
 print "AGE = ",row[2]
 print "ADDRESS = ", row[3]
 print "SALARY = ", row[4]
 print "PhoneNumber = ",row[5], "\n"
 print "Operation done successfully";
 cursor = conn.execute("select count(*) from MT_table1;")
 for row in cursor:
 print "一共有%d个用户"%row[0]

def menu():
 print '1.新增联系人'
 print '2.删除联系人'
 print '3.修改联系人'
 print '4.查询联系人'
 print '5.显示所有联系人'
 print '6.退出程序'
 print 'What do you want to do?'
while True:
 menu()
 x = raw_input('请输入您的选择菜单号:')
 if x == '1':
 insert()
 continue
 if x == '2':
 delete()
 continue
 if x == '3':
 modify()
 continue
 if x == '4':
 search()
 continue
 if x == '5':
 showall()
 continue
 if x == '6':
 print "谢谢使用!"
 exit()
 continue
 else:
 print "输入的选项不存在,请重新输入!"
 continue

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

python 通讯录