JavaScript

超轻量级php框架startmvc

mui back 返回刷新页面的实例

更新时间:2020-06-18 11:36:02 作者:startmvc
2个页面模拟1.html<!DOCTYPEhtml><html><head><metacharset="UTF-8"><title></title>

2个页面 模拟

1.html


<!DOCTYPE html>
<html>
	<head>
 <meta charset="UTF-8">
 <title></title>
 <link href="../../css/mui.min.css" rel="external nofollow" rel="external nofollow" rel="stylesheet" />
 <script src="../../../js/mui.min.js"></script>
	</head>
	<body>
 
 <script type="text/javascript" charset="utf-8">
 mui.init()
 mui.plusReady(function(){
 alert('1')
// var self=plus.webview.currentWebview();
// console.log(JSON.stringify(self)) 
 mui("body").on("tap",".a",function(){
 mui.openWindow({
 url:"2.html",
 id:"a2",
 })
 })
 });
 </script>
 
 <a href="javascript:void(0)" rel="external nofollow" rel="external nofollow" class="a">跳到a2</a>
	</body> 
</html>

2.html


<!DOCTYPE html>
<html>
	<head>
 <meta charset="UTF-8">
 <title></title>
 <link href="../../css/mui.min.css" rel="external nofollow" rel="external nofollow" rel="stylesheet" />
 <script src="../../../js/mui.min.js"></script>
	</head>
	<body>
 
 <script type="text/javascript" charset="utf-8">
 mui.init()
 mui.plusReady(function(){
// var self=plus.webview.currentWebview();
// console.log(JSON.stringify(self)) 
 var old_back = mui.back;
 mui.back = function() {
 var wobj = plus.webview.getWebviewById("HBuilder");//注意 HBuilder 是 1.html 的 ID 你如果1.html 有ID 要替换掉HBuilder,
 wobj.reload(true);
 old_back()
 }	
 });
 </script>
 
 <a href="javascript:void(0)" rel="external nofollow" rel="external nofollow" class="mui-action-back mui-icon mui-icon-left-nav mui-pull-left">返回刷新</a>
	</body>
</html>

以上这篇mui back 返回刷新页面的实例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持脚本之家。

mui back 返回 刷新 页面