将django语法和sql对应一下,希望对大家有所帮助查询单个列的值story.object.values_list("url",flat=
将django语法和sql对应一下,希望对大家有所帮助
查询单个列的值
story.object.values_list("url", flat=True)
SELECT `story`.`url` FROM `hbtc_story` WHERE `story`.`status` = resolved
AND查询
Stories.objects.filter(Q(status='resolved') & Q(status='developing'))
SELECT * FROM `story` WHERE (`story`.`status` = resolved AND `story`.`status` = developing)
或查询
Stories.objects.filter(Q(status='resolved') | Q(status='developing'))
SELECT * FROM `story` WHERE (`story`.`status` = resolved OR `story`.`status` = developing)
NOT查询
Stories.objects.filter(~Q(status='resolved'))
SELECT * FROM `story` WHERE NOT (`story`.`status` = resolved)
查询为空
Stories.objects.filter(status__isnull=True)
SELECT * FROM `story` WHERE `story`.`plan_id_id` IS NULL
like查询
Stories.objects.filter(status__contains='resolved')
SELECT * FROM `story` WHERE `story`.`status` LIKE BINARY %resolved%;
Stories.objects.filter(status__endswith='resolved')
SELECT * FROM `story` WHERE `story`.`status` LIKE BINARY %resolved;
Stories.objects.filter(status__istartswith='resolved')
SELECT * FROM `story` WHERE `story`.`status` LIKE BINARY resolved%;
in查询
Stories.objects.filter(status__in=('resolved',))
SELECT * FROM `story` WHERE `story`.`status` IN (resolved) ;
distinct查询
story.object.values_list("status", flat=True).distinct()
SELECT DISTINCT `story`.`status` FROM `story`
具体示例代码
Django查询SQL语句
# 1 res=models.Book.objects.all()
# print(res)#<QuerySet [<Book: Book object>, <Book: Book object>, <Book: Book object>, <Book: Book object>, <Book: Book object>, <Book: Book object>]>
#2 res=models.Book.objects.filter(price='555')
# print(res)#<QuerySet [<Book: 海贼王>, <Book: 哆啦A梦>]>
#3 res=models.Book.objects.get(nid=2)
# print(res.price)#三月的狮子
# res=models.Book.objects.get(nid=10)
# print(res)#只能用于一个对象的里面
#4 res=models.Book.objects.exclude(price='555')
# print(res)#<QuerySet [<Book: 百变小樱>, <Book: 三月的狮子>, <Book: 水星领航员>, <Book: 火影忍者>]>
#5 res=models.Book.objects.values('title','publishDate')
# print(res)#<QuerySet [{'title': '百变小樱', 'publishDate': datetime.date(2000, 8, 8)}, {'title': '三月的狮子', 'publishDate': datetime.date(2017, 10, 19)}, {'title': '水星领航员', 'publishDate': datetime.date(2004, 2, 23)}, {'title': '火影忍者', 'publishDate': datetime.date(1996, 1, 2)}, {'title': '海贼王', 'publishDate': datetime.date(1995, 2, 2)}, {'title': '哆啦A梦', 'publishDate': datetime.date(1969, 12, 31)}]>
#6 res=models.Book.objects.values_list('title','price')
# print(res)#<QuerySet [('百变小樱', Decimal('155.00')), ('三月的狮子', Decimal('114.00')), ('水星领航员', Decimal('999.99')), ('火影忍者', Decimal('99.20')), ('海贼王', Decimal('555.00')), ('哆啦A梦', Decimal('555.00'))]>
#7 res=models.Book.objects.filter(price='555').distinct()
# print(res)
#8 res=models.Book.objects.count()
# print(res) 6
#9 res=models.Book.objects.first()
# print(res)#百变小樱
#10 res=models.Book.objects.exists()
# print(res)#True
####################################################
#1 res=models.Book.objects.filter(price__gt=200 )
# print(res)#<QuerySet [<Book: 水星领航员>, <Book: 海贼王>, <Book: 哆啦A梦>]>
#
#2 res=models.Book.objects.filter(price__lte=555,price__gte=114)
# print(res)#<QuerySet [<Book: 百变小樱>, <Book: 三月的狮子>, <Book: 海贼王>, <Book: 哆啦A梦>]>
#3 res=models.Book.objects.filter(publishDate__year=2017)
# print(res)#<QuerySet [<Book: 三月的狮子>]>
#4 res=models.Book.objects.filter(title__startswith='水')
# print(res)#<QuerySet [<Book: 水星领航员>]>
#5 res=models.Book.objects.filter(title__contains='小')
# print(res)#<QuerySet [<Book: 百变小樱>]>
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。
djang 查询SQL语句