python实现转圈打印矩阵

本文实例为大家分享了python实现转圈打印矩阵的具体代码，供大家参考，具体内容如下#!cond

本文实例为大家分享了python实现转圈打印矩阵的具体代码，供大家参考，具体内容如下

#! conding:utf-8
__author__ = "hotpot"
__date__ = "2017/10/28 9:40"


def return_edge(matrix, start_col, end_col, start_row, end_row):
 if start_row == end_row:
 return matrix[start_row][start_col:end_col+1]
 elif end_col ==start_col:
 res = []

 for i in range(start_row,end_row+1):
 res.append(matrix[i][end_col])
 return res
 else:
 res2 =[]
 res3 =[]
 res4=[]
 res1 = matrix[start_row][start_col:end_col+1]
 for i in range(start_row+1,end_row+1):
 res2.append(matrix[i][end_col])
 for i in range(end_col-1,start_col-1,-1):
 res3.append(matrix[end_row][i])
 for i in range(end_row-1,start_row,-1):
 res4.append(matrix[i][start_row])
 res1.extend(res2)
 res1.extend(res3)
 res1.extend(res4)
 return res1
def spiralOrder( matrix):
 if matrix:
 row = len(matrix)-1
 col = len(matrix[0])-1
 start_row = 0
 start_col = 0
 end_row = row
 end_col = col
 res =[]
 while start_col<=end_col and start_row <= end_row:
 res.extend(return_edge(matrix,start_col,end_col , start_row ,end_row))
 start_col+=1
 end_col-=1
 start_row+=1
 end_row-=1
 return res
 else:
 return matrix
if __name__ == '__main__':
 matrix = [[0 for i in range(3) ]for j in range(3)]
 num=1
 for m in range(len(matrix)):
 for n in range(len(matrix[0])):
 matrix[m][n]=num
 num+=1

 print(spiralOrder( matrix))

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。

python 打印矩阵