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Python实现账号密码输错三次即锁定功能简单示例

更新时间:2020-06-28 17:54:01 作者:startmvc
本文实例讲述了Python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下

本文实例讲述了Python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:

初学Python—1


#实现账号输错三次即锁定
user = "hubery"
passwd = "123"
confirm = 0
lock=0
fileOpen = open("username.txt","a+")
fileOpen.seek(0)
for i in range(3):
 username = input("username:")
 passsword = input("password:")
 for line in fileOpen.readlines():
 if username == line.strip():
 print("账户已经锁定!")
 lock=1
 break
 else:
 continue
 fileOpen.seek(0)
 if user == username and lock ==0:
 if passwd == passsword:
 print("欢迎,欢迎!")
 confirm = 1
 break
 else:
 print("账号户或者密码错误!")
 continue
 elif lock==1:
 continue
 else:
 print("1账号或者密码错误!")
 continue
fileOpen.close()
if confirm == 0 and lock==0:
 fileWrite=open("username.txt","a")
 fileWrite.write(username+"\n")
 fileWrite.close()

基本功能可以实现;

锁定的账号为第三次输错的用户名(待完善)

以下为完善版本,如有错误,请告知


import os
user = "hubery"
passwd = "123"
count = 0
lock = 0
fileOpen = open("username.txt", "a+")
fileOpen.seek(0)
while 1:
 for i in range(5):
 username = input("username:")
 passsword = input("password:")
 for line in fileOpen.readlines():
 if username == line.strip():
 print("账户已经锁定!")
 lock = 1
 break
 else:
 continue
 fileOpen.seek(0)
 if user == username:
 if lock == 1:
 continue
 elif passsword == passwd:
 print("欢迎,欢迎!")
 os._exit(0)
 elif count < 2:
 print("账号或者密码错误!")
 count += 1
 continue
 else:
 fileOpen.write(username + "\n")
 fileOpen.flush()
 print("密码输入错误超过三次,账户已经锁定!")
 fileOpen.seek(0)
 continue
 else:
 print("账号密码错误!")
 continue
 check=input("还想验证其他账户?(yes-继续,no-退出)")
 if "no"==check.lower():
 os._exit(0)
 else:
 continue
fileOpen.close()

Python 账号密码 输错 锁定