Python批量删除只保留最近几天table的代码实例

Python批量删除table,只保留最近几天的table

代码如下：

#!/usr/bin/python3
"""
批量删除table,只保留最近几天的table
"""
import pymysql
import re
def conn_(host='',usr='',passwd='',db='',port=3306,):
 conn = pymysql.connect(host, usr, passwd, db, port,charset='utf8')
 return conn
def del_table(conn_,table_pre='',table_suff='%Y%m%d',keep_count=3):
 date_form = None
 if table_suff == "%Y%m%d":
 date_form = "_(\d{4}\d{1,2}\d{1,2})$"
 date_len = 8
 elif table_suff == "%Y-%m-%d":
 date_form = "_(\d{4}-\d{1,2}-\d{1,2})$"
 date_len = 10
 elif table_suff == "%Y%m":
 date_form = "_(\d{4}\d{1,2})$"
 date_len = 6
 elif table_suff == "%Y-%m":
 date_form = "_(\d{4}-\d{1,2})$"
 date_len = 7
 else:
 raise Exception("暂时不支持其他类型的时间后缀")
 curs = conn_.cursor()
 curs.execute('SHOW TABLES')
 data = curs.fetchall()
 table_ = r'%s'%table_pre+date_form
 list_table = []
 i = 0
 for table in data:
 mt = re.search(table_, table[0])
 if mt:
 if len(mt.groups()[0]) == date_len:
 list_table.append((table[0], mt.groups()[0]))
 i += 1
 sorted(list_table, key=lambda date: date[1]) #按照表结构后缀时间升序排序
 for j in range(i-keep_count):
 sql = 'DROP TABLE if exists %s'%list_table[j][0]
 curs.execute(sql)
 curs.close()
 conn_.close()
if __name__ == '__main__':
 table_pre = "tree_product"
 table_suff = "%Y%m%d"
 # table_suff = "%Y-%m-%d"
 # table_suff = "%Y%m"
 # table_suff = "%Y-%m"
 conn=conn_('10.0.0.11','root','sctele@root','sxf',port=3306)
 del_table(conn,table_pre=table_pre,table_suff=table_suff,keep_count=1)

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