python

超轻量级php框架startmvc

Python适配器模式代码实现解析

更新时间:2020-07-20 22:48:01 作者:startmvc
Python适配器模式,代码,思考等#-*-coding:utf-8-*-#author:baoshanclassComputer:def__init__(self,name):self.

Python适配器模式,代码,思考等


# -*- coding: utf-8 -*-
# author:baoshan
class Computer:
 def __init__(self, name):
 self.name = name
 def __str__(self):
 return 'the {} computer'.format(self.name)
 def execute(self):
 return 'executes a program'
class Synthesizer:
 def __init__(self, name):
 self.name = name
 def __str__(self):
 return 'the {} synthesizer'.format(self.name)
 def play(self):
 return 'is playing an electronic song'
class Human:
 def __init__(self, name):
 self.name = name
 def __str__(self):
 return '{} the human'.format(self.name)
 def speak(self):
 return 'says hello'
class Adapter:
 def __init__(self, obj, adapted_methods):
 self.obj = obj
 self.__dict__.update(adapted_methods)
def __str__(self):
 return str(self.obj)
def main():
 objects = [Computer('Asus')]
 synth = Synthesizer('moog')
 objects.append(Adapter(synth, dict(execute=synth.play)))
 human = Human('Bob')
 objects.append(Adapter(human, dict(execute=human.speak)))
 for i in objects:
 print('{} {}'.format(str(i), i.execute()))
if __name__ == '__main__':
 main()

代码输出:


the Asus computer executes a program
the moog synthesizer is playing an electronic song
Bob the human says hello

------------------------------------------------------------------------------------------

我们设法使得Human和Synthesizer类与客户端所期望的接口兼容,且无需改变它们的源代码。这太棒了!

这里有一个为你准备的挑战性练习,当前的实现有一个问题,当所有类都有一个属性name时,以下代码会运行失败。


 for i in objects:
 print('{}'.format(i.name))

首先想想这段代码为什么会失败?虽然从编码的角度来看这是有意义的,但对于客户端代码来说毫无意义,客户端不应该关心“适配了什么”和“什么没有被适配”这类细节。我们只是想提供一个统一的接口。该如何做才能让这段代码生效?

思考一下如何将未适配部分委托给包含在适配器类中的对象。

答案如下:

将适配器类更改如下,增加一行代码


class Adapter:
 def __init__(self, obj, adapted_methods):
 self.obj = obj
 self.__dict__.update(adapted_methods)
 self.name = obj.name
 def __str__(self):
 return str(self.obj)

然后在main函数中获取对应的name,如下


def main():
 objects = [Computer('Asus')]
 synth = Synthesizer('moog')
 objects.append(Adapter(synth, dict(execute=synth.play)))
 human = Human('Bob')
 objects.append(Adapter(human, dict(execute=human.speak)))
 for i in objects:
 print('{} {}'.format(str(i), i.execute()))
 print('{}'.format(i.name))
if __name__ == '__main__':
 main()

输出结果如下:


the Asus computer executes a program
Asus
the moog synthesizer is playing an electronic song
moog
Bob the human says hello
Bob

参考自:《精通Python设计模式》

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

python 适配器模式 代码