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超轻量级php框架startmvc

python实现静态服务器

更新时间:2020-07-29 16:30:01 作者:startmvc
本文实例为大家分享了python静态服务器的具体代码,供大家参考,具体内容如下#coding:utf-8im

本文实例为大家分享了python静态服务器的具体代码,供大家参考,具体内容如下


#coding:utf-8
import socket
import multiprocessing
import re


HTML_ROOT_DIR = "./html"

class HTTPServer(object):

 #初始化
 def __init__(self):
 self.serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
 self.serversocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


 #开启服务器启动进程
 def start(self):
 self.serversocket.listen(128)
 while True:
 clintsocket, addree = self.serversocket.accept()
 hanlderprogess = multiprocessing.Process(target=self.xiexi, args=(clintsocket,))
 hanlderprogess.start()
 clintsocket.close()

 #绑定端口
 def bind(self,port):
 self.serversocket.bind(("", port))


 #获取请求头,进行解析,同时发送相应头
 def xiexi(clserver):
 date = clserver.recv(1024)
 print date
 list = str(date).split("\r\n")
 # 解析
 requesthead = list[0]
 print requesthead
 #使用正则表达式解析出请求头的文件名称
 file = re.match(r"\w+ +(/[^ ]*) ",requesthead).group(1)

 #对获取的问题名判断,如果是/的就进行显示index.html
 if "/"==file:
 file = "/index.html"
 try:
 f = open(HTML_ROOT_DIR+file,"rb")
 except:
 response_start_line = "HTTP/1.1 200 OK \r\n"
 response_headers = "Server:My server\r\n"
 response_body = "the file not file"
 else:
 file_date = f.readline()
 f.close()
 response_start_line = "HTTP/1.1 200 OK \r\n"
 response_headers = "Server:My server\r\n"
 response_body = file_date.decode("utf-8")

 response = response_start_line+response_headers+"\r\n"+response_body
 print response
 clserver.send(bytes(response))
 clserver.close()

def main():
 server = HTTPServer()
 server.bind(1001)
 server.start()

if __name__=="__main__":
 main()

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

python 静态服务器