TP5框架简单登录功能实现方法示例

本文实例讲述了TP5框架简单登录功能实现方法。分享给大家供大家参考，具体如下：登录方

本文实例讲述了TP5框架简单登录功能实现方法。分享给大家供大家参考，具体如下：

登录方法,验证

public function login()
{
 if(request()->isGet()){
 return view('login');
 }elseif(request()->isPost()){
 $model = new InfoModel(); 
 $name = input('name'); //获取表单提交的姓名
 $pwd = input('password');//获取表单提交的密码
 if($model->LoginVerify($name,$pwd)){
 $verify = input('code'); //获取验证码的值
 $cap = new Captcha(); //实例化验证码类
 if($cap->check($verify)){
 $this->success('登录成功','admin/ShowIndex');//登录成功跳转首页
 /*echo '登录成功';*/
 }else{
 $this->error('验证码错误','admin/admin/login');
 }
 }
 }
}

表单

<div class="form-group">
 <div class="field field-icon-right">
 <input type="password" class="input input-big" name="password" placeholder="登录密码" data-validate="required:请填写密码" />
 <span class="icon icon-key margin-small"></span>
 </div>
 </div>
 <div class="form-group">
 <div class="field">
 <input type="text" class="input input-big" name="code" placeholder="填写右侧的验证码" data-validate="required:请填写右侧的验证码" />
 <img src="{:captcha_src()}" alt="" width="150" height="32" class="passcode" style="height:43px;cursor:pointer;" οnclick="this.src=this.src+'?'"> 
 </div>
</div>

model类,要与表名同名

<?php
namespace app\admin\model;
use think\Model;
class Info extends Model
{
#登录验证
 public function LoginVerify($name,$pwd)
 {
 //$re = $this->where(["username =>'$name',pwd=>'$pwd'"])->find();
 $re = $this->where("username='$name' and pwd='$pwd'")->find();
 if($re){
 return $re;
 }else{
 return null;
 }
 }
}