python

超轻量级php框架startmvc

python调用接口的4种方式代码实例

更新时间:2020-08-08 12:36:01 作者:startmvc
这篇文章主要介绍了python调用接口的4种方式代码实例,文中通过示例代码介绍的非常详细,

这篇文章主要介绍了python调用接口的4种方式代码实例,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

python中调用API的几种方式:

  • - urllib2
  • - httplib2
  • - pycurl
  • - requests

1.urllib2


import urllib2, urllib
github_url =
	'https://api.github.com/user/repos'
password_manager = urllib2.HTTPPasswordMgrWithDefaultRealm()
password_manager.add_password(None,
	github_url, 'user', '***')
auth = urllib2.HTTPBasicAuthHandler(
	password_manager)# create an authentication handler
opener = urllib2.build_opener(auth)# create an opener with the authentication handler
urllib2.install_opener(opener)# install the opener
	...
request = urllib2.Request(github_url,
	urllib.urlencode({
 'name': 'Test repo',
 'description': 'Some test repository'
	}))# Manual encoding required
handler = urllib2.urlopen(request)
print handler.read()

2. httplib2


import urllib, httplib2
github_url = '
h = httplib2.Http(".cache")
h.add_credentials("user", "******", "
 data = urllib.urlencode({
 "name": "test"
 }) resp, content = h.request(
 github_url, "POST", data) print content

3. pycurl


import pycurl, json
github_url = "
user_pwd = "user:*****"
data = json.dumps({
	"name": "test_repo",
	"description": "Some test repo"
})
c = pycurl.Curl()
c.setopt(pycurl.URL, github_url)
c.setopt(pycurl.USERPWD, user_pwd)
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()

4. requests


import requests, json
github_url = "
data = json.dumps({'name':'test', 'description':'some test repo'}) 
r = requests.post(github_url, data, auth=('user', '*****'))
print r.json

以上几种方式都可以调用API来执行动作,但requests这种方式代码最简洁,最清晰,建议采用。

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。