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python实现kMeans算法

更新时间:2020-05-15 04:54:01 作者:startmvc
聚类是一种无监督的学习,将相似的对象放到同一簇中,有点像是全自动分类,簇内的对象

聚类是一种无监督的学习,将相似的对象放到同一簇中,有点像是全自动分类,簇内的对象越相似,簇间的对象差别越大,则聚类效果越好。

1、k均值聚类算法

k均值聚类将数据分为k个簇,每个簇通过其质心,即簇中所有点的中心来描述。首先随机确定k个初始点作为质心,然后将数据集分配到距离最近的簇中。然后将每个簇的质心更新为所有数据集的平均值。然后再进行第二次划分数据集,直到聚类结果不再变化为止。

伪代码为

随机创建k个簇质心 当任意一个点的簇分配发生改变时:     对数据集中的每个数据点:         对每个质心:             计算数据集到质心的距离         将数据集分配到最近距离质心对应的簇     对每一个簇,计算簇中所有点的均值并将均值作为质心

python实现


import numpy as np
import matplotlib.pyplot as plt

def loadDataSet(fileName): 
 dataMat = [] 
 with open(fileName) as f:
 for line in f.readlines():
 line = line.strip().split('\t')
 dataMat.append(line)
 dataMat = np.array(dataMat).astype(np.float32)
 return dataMat


def distEclud(vecA,vecB):
 return np.sqrt(np.sum(np.power((vecA-vecB),2)))
def randCent(dataSet,k):
 m = np.shape(dataSet)[1]
 center = np.mat(np.ones((k,m)))
 for i in range(m):
 centmin = min(dataSet[:,i])
 centmax = max(dataSet[:,i])
 center[:,i] = centmin + (centmax - centmin) * np.random.rand(k,1)
 return center
def kMeans(dataSet,k,distMeans = distEclud,createCent = randCent):
 m = np.shape(dataSet)[0]
 clusterAssment = np.mat(np.zeros((m,2)))
 centroids = createCent(dataSet,k)
 clusterChanged = True
 while clusterChanged:
 clusterChanged = False
 for i in range(m):
 minDist = np.inf
 minIndex = -1
 for j in range(k):
 distJI = distMeans(dataSet[i,:],centroids[j,:])
 if distJI < minDist:
 minDist = distJI
 minIndex = j
 if clusterAssment[i,0] != minIndex:
 clusterChanged = True
 clusterAssment[i,:] = minIndex,minDist**2
 for cent in range(k):
 ptsInClust = dataSet[np.nonzero(clusterAssment[:,0].A == cent)[0]]
 centroids[cent,:] = np.mean(ptsInClust,axis = 0)
 return centroids,clusterAssment



data = loadDataSet('testSet.txt')
muCentroids, clusterAssing = kMeans(data,4)
fig = plt.figure(0)
ax = fig.add_subplot(111)
ax.scatter(data[:,0],data[:,1],c = clusterAssing[:,0].A)
plt.show()

print(clusterAssing)

2、二分k均值算法

K均值算法可能会收敛到局部最小值,而非全局最小。一种用于度量聚类效果的指标为误差平方和(SSE)。因为取了平方,更加重视原理中心的点。为了克服k均值算法可能会收敛到局部最小值的问题,有人提出来二分k均值算法。 首先将所有点作为一个簇,然后将该簇一分为二,然后选择所有簇中对其划分能够最大程度减低SSE的值的簇,直到满足指定簇数为止。

伪代码

将所有点看成一个簇 计算SSE while 当簇数目小于k时:     for 每一个簇:         计算总误差         在给定的簇上进行k均值聚类(k=2)         计算将该簇一分为二的总误差     选择使得误差最小的那个簇进行划分操作

python实现


import numpy as np
import matplotlib.pyplot as plt

def loadDataSet(fileName): 
 dataMat = [] 
 with open(fileName) as f:
 for line in f.readlines():
 line = line.strip().split('\t')
 dataMat.append(line)
 dataMat = np.array(dataMat).astype(np.float32)
 return dataMat


def distEclud(vecA,vecB):
 return np.sqrt(np.sum(np.power((vecA-vecB),2)))
def randCent(dataSet,k):
 m = np.shape(dataSet)[1]
 center = np.mat(np.ones((k,m)))
 for i in range(m):
 centmin = min(dataSet[:,i])
 centmax = max(dataSet[:,i])
 center[:,i] = centmin + (centmax - centmin) * np.random.rand(k,1)
 return center
def kMeans(dataSet,k,distMeans = distEclud,createCent = randCent):
 m = np.shape(dataSet)[0]
 clusterAssment = np.mat(np.zeros((m,2)))
 centroids = createCent(dataSet,k)
 clusterChanged = True
 while clusterChanged:
 clusterChanged = False
 for i in range(m):
 minDist = np.inf
 minIndex = -1
 for j in range(k):
 distJI = distMeans(dataSet[i,:],centroids[j,:])
 if distJI < minDist:
 minDist = distJI
 minIndex = j
 if clusterAssment[i,0] != minIndex:
 clusterChanged = True
 clusterAssment[i,:] = minIndex,minDist**2
 for cent in range(k):
 ptsInClust = dataSet[np.nonzero(clusterAssment[:,0].A == cent)[0]]
 centroids[cent,:] = np.mean(ptsInClust,axis = 0)
 return centroids,clusterAssment

def biKmeans(dataSet,k,distMeans = distEclud):
 m = np.shape(dataSet)[0]
 clusterAssment = np.mat(np.zeros((m,2)))
 centroid0 = np.mean(dataSet,axis=0).tolist()
 centList = [centroid0]
 for j in range(m):
 clusterAssment[j,1] = distMeans(dataSet[j,:],np.mat(centroid0))**2
 while (len(centList)<k):
 lowestSSE = np.inf
 for i in range(len(centList)):
 ptsInCurrCluster = dataSet[np.nonzero(clusterAssment[:,0].A == i)[0],:]
 centroidMat,splitClustAss = kMeans(ptsInCurrCluster,2,distMeans)
 sseSplit = np.sum(splitClustAss[:,1])
 sseNotSplit = np.sum(clusterAssment[np.nonzero(clusterAssment[:,0].A != i)[0],1])
 if (sseSplit + sseNotSplit) < lowestSSE:
 bestCentToSplit = i
 bestNewCents = centroidMat.copy()
 bestClustAss = splitClustAss.copy()
 lowestSSE = sseSplit + sseNotSplit
 print('the best cent to split is ',bestCentToSplit)
# print('the len of the bestClust')
 bestClustAss[np.nonzero(bestClustAss[:,0].A == 1)[0],0] = len(centList)
 bestClustAss[np.nonzero(bestClustAss[:,0].A == 0)[0],0] = bestCentToSplit

 clusterAssment[np.nonzero(clusterAssment[:,0].A == bestCentToSplit)[0],:] = bestClustAss.copy()
 centList[bestCentToSplit] = bestNewCents[0,:].tolist()[0]
 centList.append(bestNewCents[1,:].tolist()[0])
 return np.mat(centList),clusterAssment

data = loadDataSet('testSet2.txt')
muCentroids, clusterAssing = biKmeans(data,3)
fig = plt.figure(0)
ax = fig.add_subplot(111)
ax.scatter(data[:,0],data[:,1],c = clusterAssing[:,0].A,cmap=plt.cm.Paired)
ax.scatter(muCentroids[:,0],muCentroids[:,1])
plt.show()

print(clusterAssing)
print(muCentroids)

代码及数据集下载:K-means

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python kMeans